Java2 test

[Bravomail]

Dano:

public void printVector (ArrayList vec) {
Object item;
while (vec.listIterator().hasNext()) {
item=vec.listIterator().next();
System.out.println(item.toString());
}
}

Итак - на глаз виден цикл выдающий все элементы на консоль.
Некоторая неоптимальность кодирования -
не обращайте на это внимания.
Вопрос - будет ли работать эта программа?

[AK70]

vec.listIterator()

will bring the new itereator at every call [img:7f133d1ea1]images/smiles/icon_smile.gif[/img:7f133d1ea1]

[Bravomail]

<BLOCKQUOTE><font size="1" face="Arial, Verdana, Helvetica, sans-serif">quote:</font><HR>Originally posted by AK70:
<STRONG>vec.listIterator()

will bring the new itereator at every call [img:ef53b21a43]images/smiles/icon_smile.gif[/img:ef53b21a43]</STRONG><HR></BLOCKQUOTE>

So loop will be indefinite long.
That's actually taken out of real code. It was really interesting for me to realize that "nonoptimized" code sometimes doesn't work, even if it looks so
.

[AK70]

<BLOCKQUOTE><font size="1" face="Arial, Verdana, Helvetica, sans-serif">quote:</font><HR>Originally posted by Bravomail:
<STRONG>

So loop will be indefinite long.
</STRONG><HR></BLOCKQUOTE>

not necessarily. you pass the reference to the function. which means that you can empty the ArrayList in another thread. then your hasNext() will return "false" and the loop will end.

definitely, it's the bug

[ 29-10-2001: Message edited by: AK70 ]